warchild
Charter Member
I honestly think we're all saying th exact same thing here, just using different terms to define it. Bjoerns video of the F-104 certainly shows what we're discusing. Gyroscopic force is whats driving it and centripetal force is whats causing it.
No, Centripetal force is not glue that holds things together.. Here.. a grade school definition..
[h=1]What is a centripetal force?[/h]A centripetal force is a net force that acts on an object to keep it moving along a circular path.
In our article on centripetal acceleration, we learned that any object traveling along a circular path of radius rrrr with velocity vvvv experiences an acceleration directed toward the center of its path,
a=v2ra = \frac{v^2}{r}a=r
v2a, equals, start fraction, v, start superscript, 2, end superscript, divided by, r, end fraction.
However, we should discuss how the object came to be moving along the circular path in the first place. Newton’s 1ˢᵗ law tells us that an object will continue moving along a straight path unless acted on by an external force. The external force here is the centripetal force.
It is important to understand that the centripetal force is not a fundamental force, but just a label given to the net force which causes an object to move in a circular path. The tension force in the string of a swinging tethered ball and the gravitational force keeping a satellite in orbit are both examples of centripetal forces. Multiple individual forces can even be involved as long as they add up (by vector addition) to give a net force towards the center of the circular path.
Starting with Newton's 2ⁿᵈ law :
a=Fma = \frac{F}{m}a=m
Fa, equals, start fraction, F, divided by, m, end fraction
and then equating this to the centripetal acceleration,
v2r=Fm\frac{v^2}{r} = \frac{F}{m}r
v2=m
Fstart fraction, v, start superscript, 2, end superscript, divided by, r, end fraction, equals, start fraction, F, divided by, m, end fraction
We can show that the centripetal force FCF_CFCF, start subscript, C, end subscript has magnitude
Fc=mv2rF_c = \frac{mv^2}{r}Fc=r
mv2F, start subscript, c, end subscript, equals, start fraction, m, v, start superscript, 2, end superscript, divided by, r, end fraction
and is always directed towards the center of the circular path. Equivalently, if ω\omegaωomega is the angular velocity then because v=rωv=r\omegav=rωv, equals, r, omega,
Fc=mrω2F_c = m r \omega^2Fc=mrω2
Like i said, we're all saying the same thing, we're just using different terms and maybe perhaps focusing on seperate components of the phenomena..
Pam
No, Centripetal force is not glue that holds things together.. Here.. a grade school definition..
[h=1]What is a centripetal force?[/h]A centripetal force is a net force that acts on an object to keep it moving along a circular path.
In our article on centripetal acceleration, we learned that any object traveling along a circular path of radius rrrr with velocity vvvv experiences an acceleration directed toward the center of its path,
a=v2ra = \frac{v^2}{r}a=r
v2a, equals, start fraction, v, start superscript, 2, end superscript, divided by, r, end fraction.
However, we should discuss how the object came to be moving along the circular path in the first place. Newton’s 1ˢᵗ law tells us that an object will continue moving along a straight path unless acted on by an external force. The external force here is the centripetal force.
It is important to understand that the centripetal force is not a fundamental force, but just a label given to the net force which causes an object to move in a circular path. The tension force in the string of a swinging tethered ball and the gravitational force keeping a satellite in orbit are both examples of centripetal forces. Multiple individual forces can even be involved as long as they add up (by vector addition) to give a net force towards the center of the circular path.
Starting with Newton's 2ⁿᵈ law :
a=Fma = \frac{F}{m}a=m
Fa, equals, start fraction, F, divided by, m, end fraction
and then equating this to the centripetal acceleration,
v2r=Fm\frac{v^2}{r} = \frac{F}{m}r
v2=m
Fstart fraction, v, start superscript, 2, end superscript, divided by, r, end fraction, equals, start fraction, F, divided by, m, end fraction
We can show that the centripetal force FCF_CFCF, start subscript, C, end subscript has magnitude
Fc=mv2rF_c = \frac{mv^2}{r}Fc=r
mv2F, start subscript, c, end subscript, equals, start fraction, m, v, start superscript, 2, end superscript, divided by, r, end fraction
and is always directed towards the center of the circular path. Equivalently, if ω\omegaωomega is the angular velocity then because v=rωv=r\omegav=rωv, equals, r, omega,
Fc=mrω2F_c = m r \omega^2Fc=mrω2
Like i said, we're all saying the same thing, we're just using different terms and maybe perhaps focusing on seperate components of the phenomena..
Pam